Answer: C Circumference of circle = perimeter of rhombus 2*22/7 * 35 = 4 * x Side of rhombus(x) =55 cm.

Q. No. 2:

The dimensions of a rectangular box are in the ratio 1:2:4 and the difference between costs of covering in with the cloth and sheet at the rate of Rs 20 and Rs 20.5 per sq m respectively is Rs 126. Find the dimensions of the box.

Answer: A Let the length =x, breadth =2x and height =4x Then area of the box = 2(lb+bh+hl) = (2(x^{2}) + 8(x^{2}) + 4(x^{2})) = 28x^{2} Given, (20.5*28x^{2}) -(20*28x^{2}) =126 x^{2}=9 or x=3 Dimensions are 3,6,12

Q. No. 3:

The height of a bucket is 45cm. The radii of the two circular ends are 28cm and 7 cm respectively. The volume of the bucket is

Answer: C Let the upper(small ) radius of bucket is(r)= 7cm and the bigger radius be R= 28 cm , height =45 cm Volume of the bucket = 1/3 * 22/7 * h(r^{2}+R^{2}+rR) = 48510cm^{3}

Q. No. 4:

A track is in the form of ring whose inner circumference is 352 m and the outer circumference is 396 m. The width of the track is

Answer: D Let the inner radius be rand outer radius be R Then, 2*pie*r =352m => r= 352/(2*pie) 2*pie*R =396 => R = 396/(2*pie) Width of the track = (R-r) = (396-352)/(2*pie) = 7m

Q. No. 5:

A person wishes to make a 100 sq m rectangular garden. Since he has only 30m barbed wire for fencing, he fences only three sides letting the house wall act as the fourth side. The width of the garden is

Answer: B Let, the length be 'l' and breadth be 'b'. Thus, l*b =100 => l= 100/b 100/b +b+b = 30 By solving this we get b= 10 and 5. b is not equal to 10 because it will become square. so, b=5m is the answer.

Q. No. 6:

By what percent the volume of cube increases, if the length of each edge was increased by 50%.

Answer: A Let the original side of the cube be 10 cm. Then volume = 10*10*10 = 1000 New side =15 New volume = 15*15*15 = 3375 % increases in volume = (3375-1000)*100/1000 = 237.5%