There are two machines X and Y .X produces 100X /min and takes rest of 5 min to clean after 1000X . And Y produces 75Y/min and takes 10 min rest after a production of 1500Y .what will be minimum time after which 9000 pair of X,Y will be produced............
a) 135
b) 130
c) 170
d) 180

(ITC Infotech Question)
Dinesh Tripathi   130
6 years ago
Ashish Bhandari   a 135
6 years ago
dipak kumar dubey   170
6 years ago
munna bhai   170
6 years ago
Sayandeep Nandy   170
6 years ago
Sushil Kumar   170
6 years ago
Disary Nath Sarkar   170
6 years ago
riya ghosh   plz explain..
6 years ago
mousumi roy   For machine X100 X -> 1 min1000 X -> 10 min + 5 min clean = 15 minSo, 9000 X -> 15*9 = 135 minBut the last 5 min would be for cleaningSo, 9000 X can be produced by X in 130 minFor machine Y75 Y -> 1 minSo, 1500 Y -> 20 min + 10 min rest = 30 minSo, 9000 Y -> 30*6 = 180 minBut the last 10 min would be for rest. So, 9000 Y can be made in 170 minDesired Answer = Max(min(X,Y)) = Max(130,170) = 170 min
6 years ago
RAJAT   170
2 years ago

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