Which polygon has no. of sides = diagonal
Asked by Pritha sharma
Abhinay Madasu   Pentagon
7 years ago
Anurag Kumar   No of diagonols = nC2-n
No of sides = n
ATQ(According to Ques)
=>n= nC2-n
=>2n = n(n-2)/2
n=5
Therefore,answer is pentagon.
7 years ago
yogesh   replace n-2 by n-1
6 years ago
ujjawal sharma   pentagon
6 years ago
salman   anurag > canu tell me 6th step
6 years ago

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