be * be = acb
A,b,c,e are non zero numbers find b,e.
Asked by Saikat
yatish   19*19=361

b=1
e=9
a=3
c=6
7 years ago
sd   a=2
b=2
c=2
e=4
7 years ago
nalini tanwer   a=3
b=1
c=6
e=9
7 years ago
Jyoti Ranjan Mohapatra   19
7 years ago
k udayakumar   a =1
b=4
c=4
e =3
7 years ago
Sumit   a=1
c=2
b=1
e=1
7 years ago
prabhakar kumar sah   a=2
b=1
c=8
e=4
7 years ago
Saptarshi Ghosh   Ans b=1
e=1
7 years ago
Amit   It could be 19 or 29.
That is b=1 or 2,but e=9.
6 years ago
yugandhar   only 19.
b=1, e=9.
6 years ago
sree   hw to approach such qstns....plz help me?
6 years ago
manisha mohanty   plz do x'plain this particular question,,,,
6 years ago
harry   it can b 11*11=121 or 19*19=361
6 years ago
Ghazala Farheen   be can be any to digit num lik 11 to 19 and corresponding acb can be any of 121 or 361!!
6 years ago
Sourajya Kumar Bisoyi   here,it's nt been mentioned that a,b,c,e are distinct....so,ans?
5 years ago
Fouzia Khatoon   It may be 19 or 11 as
be * be= acb

i.e square of two digit number has to three in digit i.e acb

19 * 19= 361
11 * 11= 121

5 years ago
anand   How to solve this type of question?? Can anyone explqin??
5 years ago
srikanth   B=1 E=9
5 years ago
naina   b=1 e=9
5 years ago
sumit shekhar   19
4 years ago
manasa   it is crypt arithmetic problem go through that concept
3 years ago
munmun mohapatra   19
3 years ago
R.RAMYA   its 19* 19 only because, all the values a,b,c,e are distinct values. if you take 11 as the answer, that means a,e,b,c all have the same value 1 and b has another value=2 in the right hand side. so 11 is not the answer
2 years ago

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