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 be * be = acb A,b,c,e are non zero numbers find b,e. Asked by SaikatCompile Program
 yatish   19*19=361 b=1 e=9 a=3 c=6 8 years ago
 sd   a=2 b=2 c=2 e=4 7 years ago
 nalini tanwer   a=3 b=1 c=6 e=9 7 years ago
 Jyoti Ranjan Mohapatra   19 7 years ago
 k udayakumar   a =1 b=4 c=4 e =3 7 years ago
 Sumit   a=1 c=2 b=1 e=1 7 years ago
 prabhakar kumar sah   a=2 b=1 c=8 e=4 7 years ago
 Saptarshi Ghosh   Ans b=1 e=1 7 years ago
 Amit   It could be 19 or 29. That is b=1 or 2,but e=9. 7 years ago
 yugandhar   only 19. b=1, e=9. 7 years ago
 sree   hw to approach such qstns....plz help me? 7 years ago
 manisha mohanty   plz do x'plain this particular question,,,, 7 years ago
 harry   it can b 11*11=121 or 19*19=361 6 years ago
 Ghazala Farheen   be can be any to digit num lik 11 to 19 and corresponding acb can be any of 121 or 361!! 6 years ago
 Sourajya Kumar Bisoyi   here,it's nt been mentioned that a,b,c,e are distinct....so,ans? 5 years ago
 Fouzia Khatoon   It may be 19 or 11 as be * be= acb i.e square of two digit number has to three in digit i.e acb 19 * 19= 361 11 * 11= 121 5 years ago
 anand   How to solve this type of question?? Can anyone explqin?? 5 years ago
 srikanth   B=1 E=9 5 years ago
 naina   b=1 e=9 5 years ago
 sumit shekhar   19 4 years ago
 manasa   it is crypt arithmetic problem go through that concept 3 years ago
 munmun mohapatra   19 3 years ago
 R.RAMYA   its 19* 19 only because, all the values a,b,c,e are distinct values. if you take 11 as the answer, that means a,e,b,c all have the same value 1 and b has another value=2 in the right hand side. so 11 is not the answer 2 years ago