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 A circular dartboard of radius 1 foot is at a distance of 20 feet from you. You throw a dart at it and it hits the dartboard at some point Q in the circle. What is the probability that Q is closer to the center of the circle than the periphery? a) 0.75 b) 1 c) 0.5 d) 0.25 (TCS Question) Asked by anshuCompile Program
 vijaya lakshmi   d) 7 years ago
 somnath   how.plzz xplain............. 7 years ago
 Pritam Maity   d) coz it hv 4 circle 1. bull's eye 2. bull 3. triple ring 4. double ring. so prb is 1/4=0.25 7 years ago
 Kirti reddy   Here the distance 20 feet is irrelevant. Don't think of it. Make a circle of radius r and inside another circle of radius r/2. Consider the general situation i.e radius = r.​ Now we divide the dart board into two halves. Any point in the inner circle is clearly closer to the center than perifery since we have divided the circle as r/2 and r/2. The dart can hit at any point in the circle. So total sample space is whole area of the circle = (pi)​(r2)----------eq(1). Now we need to find area of the inner circle. Its (pi)*(r/2)2​= (pi)*​​(r2/4)-----------eq(2)​. Probability is (required event)/(sample space) = ​eq(2)/eq(1) = 1/4=0.25.​ 7 years ago
 Abhishek   (d) 0.25 =(pi(1/2)^2)/(pi.1^2) =(1/2)^2 =1/4 =0.25 7 years ago
 Subhajit Pramanik   0.25 6 years ago
 ratikant patra   0.25 6 years ago
 akash bhargava   kirti reddy is absolutely right. 6 years ago
 sasidhar kumar   ans is 0.25 whole circle area is pi(r^2),inner circle area is pi(r/2)^2 then equation 2 by eqution 1then u get 0.25 4 years ago