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 A thief steals a car at 2.30 p.m and drives it at 60 kmph. The theft is discovered at 3 p.m and the owner sets off in another car at 75 kmph. When will be overtake the thief. A) 4.30 p.m B) 4.45 p.m C) 5 p.m D) 5.15 p.m (Wipro Question) Asked by Priya kumariCompile Program
 praveen kumar   a) at 4:30pm 7 years ago
 Shalu Jain   c)5 p.m 7 years ago
 amit prasad   5 pm....quite easy 7 years ago
 K BASHA   Ans c)5 pm 7 years ago
 vjndra   5pm 7 years ago
 ARUP CHOWDHURY   pls deatil solution 7 years ago
 debadatta biswal   As the theft is discovered at 3:00pm and the thief stole the car at 2:30. Which means thief covered some distance in this 30 min gap. Distance travelled by thief from 2.30 to 3.00 is 60 * 1/2 = 30 km At 3:00 pm, Owner--> <----------30km---------> Thief--> Now concept of relative speed the time at which owner meets thief is 30/(70-65) = 2 hrs So After 2 hrs (i.e,at 5:00 pm) the owner will catch/overtake the thief 7 years ago
 Arijit Das   5pm 7 years ago
 kumar aara   time thief owner 2.30 0 0 3 30 0 3.30 60 37.5 4 90 75 4.30 120 112.5 5 150 150 7 years ago
 Abhishek Bharti   5pm 7 years ago
 MANOJ   5pm 7 years ago
 Anant   at 5pmhewill run 150in 2.30 and other willrun 150 i 2hr 7 years ago
 Anant   both will be in equail ditance 7 years ago
 shivam   at 5.15 pm 7 years ago
 manoj singh rautela   at 5 pm........! 7 years ago
 Irfan khan   time thief(travel) owner(travel) 2:30 0 0 3:00 30 km 0 km 4:00 90 km 75 km 5:00 150 150 km ,,, hence 5:00pm is the right answer.. 7 years ago
 karthickeyan   5 pm........! 7 years ago
 magyy   => 60t=75(t-0.5) => t=2.5 owner meets thief after (t-0.5) i.e after 2 hours so, 3.00 p.m+2 hours= 5.00 p.m....... :):) 7 years ago
 rahul   5 pm its too obvious....:) 6 years ago
 Lucy Desouza   Since in 1/2 hour thief will cover 30 km..Which means he is 30 km ahead now from the owner.So The owner minimises 15 km in 1 hour as speed is 75 km and thief speed is 60 km ...so to cover 30 km it needs 2 hour ..so time will be 3+ 2 = 5 Pm :) 6 years ago
 Punit mishra   answer is 5 pm in these cases d=(extra distance/relative speed)*greater speed 5 years ago
 Mythreyee   nice explanation. 4 years ago