Two trains each 100 m long, moving in opposite directions, cross each other in 8 seconds. If one is moving twice as fast
the other, then the speed of the faster train is

A) 30 km /hr B) 45 km / hr C) 60 km/hr D) 75 km/hr
(Wipro Question)
Asked by Priya kumari
mukesh kumar pandey   Let the speed of the slower train be x m/sec.

Then, speed of the faster train = 2x m/sec.

Relative speed = (x + 2x) m/sec = 3x m/sec.

(100 + 100) = 3x
8
24x = 200

x = 25 .
3
So, speed of the faster train = 50 m/sec
3
= 50 x 18 km/hr
3 5
= 60 km/hr.
7 years ago
K BASHA   (100+100)/8= 3x*5/18

so x=60 km/hr
7 years ago
vjndra   60km/hr
7 years ago
arunkumar   a
7 years ago
swati gaur   30km/hr
7 years ago
Arijit Das    60km/hr
7 years ago
MANOJ   60 km/hr
6 years ago
ravi madhukar   distance will we added because both are opp to each other so distance =200km.
relative speed = 25m/s
let one's speed is 'x'
another will be 2x
so relative speed = 2x+x=25*18/5
value of x=30km/h
faster train's speed = 60km/h
6 years ago
r   60km/h
6 years ago
shailendra singh   60km/h
5 years ago
NILESH   60 km/hr
5 years ago
Govind Singh Choudhary   60km/hr
5 years ago
anuj   60
4 years ago
d.ayyappa   60
4 years ago
Nikhil R. Newhale   length of 2 trains =200
let speed be x & 2x =3x
length of both the trains(200)*18/5=90
x+2x=90
3x=90
x=30
speed of fastest train(2x)
2*30=60km/hr.
4 years ago
kiran   60km/hr
3 years ago
shankar prasad   guys how are you getting this 18/5 ?
one year ago

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