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 Two trains each 100 m long, moving in opposite directions, cross each other in 8 seconds. If one is moving twice as fast the other, then the speed of the faster train is A) 30 km /hr B) 45 km / hr C) 60 km/hr D) 75 km/hr (Wipro Question) Asked by Priya kumariCompile Program
 mukesh kumar pandey   Let the speed of the slower train be x m/sec. Then, speed of the faster train = 2x m/sec. Relative speed = (x + 2x) m/sec = 3x m/sec. (100 + 100) = 3x 8 24x = 200 x = 25 . 3 So, speed of the faster train = 50 m/sec 3 = 50 x 18 km/hr 3 5 = 60 km/hr. 7 years ago
 K BASHA   (100+100)/8= 3x*5/18 so x=60 km/hr 7 years ago
 vjndra   60km/hr 7 years ago
 arunkumar   a 7 years ago
 swati gaur   30km/hr 7 years ago
 Arijit Das    60km/hr 7 years ago
 MANOJ   60 km/hr 7 years ago
 ravi madhukar   distance will we added because both are opp to each other so distance =200km. relative speed = 25m/s let one's speed is 'x' another will be 2x so relative speed = 2x+x=25*18/5 value of x=30km/h faster train's speed = 60km/h 7 years ago
 r   60km/h 6 years ago
 shailendra singh   60km/h 5 years ago
 NILESH   60 km/hr 5 years ago
 Govind Singh Choudhary   60km/hr 5 years ago
 anuj   60 4 years ago
 d.ayyappa   60 4 years ago
 Nikhil R. Newhale   length of 2 trains =200 let speed be x & 2x =3x length of both the trains(200)*18/5=90 x+2x=90 3x=90 x=30 speed of fastest train(2x) 2*30=60km/hr. 4 years ago
 kiran   60km/hr 3 years ago
 shankar prasad   guys how are you getting this 18/5 ? 2 years ago