•  Questions
 Profile
 Profile
 Interview
 Fake Interview
 If a car starts from A towards B with some velocity. Due to some problem in the engine after traveling 30km, the car goes with 4/5 th of its actual velocity The car reaches B 45 min later to the actual time. If the car engine fails after traveling 45km, the car reaches the destination B 36min late to the actual time What is the initial velocity of car and what is the distance between A and B in km. (IBM Question) Asked by SatishCompile Program
 Ranendra kumar   v=25 and x=105 7 years ago
 tapas   30/v+5(x-30)/4v=(t+45); 45/v+5(x-45)/4v=(t+36); where vt=x; 7 years ago
 sravanthi   can anyone solve this and post the answer 7 years ago
 Paritosh   Let x be the distance between A and B. Let v be the speed and t be the actual time. vt=x ..... (i) Now time taken during first 30km = 30/v Time taken during next (x-30) km = (x-30)/(4/5v) According to question total time taken = t+45 So 30/v+5(x-30)/4v=(t+45) ..... (ii) Similarly In second case 45/v+5(x-45)/4v=(t+36) .....(iii) From (ii) 120 + 5x-150 = 4vt+180v or, 5x -30 = 4x + 180v or, v = (x-30)/180 ... (iv) From (iii) 180 + 5x-225 = 4vt+144v or, 5x - 45 = 4x + 144v or, v = (x - 45)/144 ... (v) From (iv) and (v) (x-30)144 = (x-45)180 or, 4x-120 = 5x - 225 or, x = 105 km 7 years ago
 subhadip mukherjee   (5(d-30)/4x)-((d-30)/x)=45,2nd case also similar,ans is 75 7 years ago
 Rohini Goyal   45 K.m. 6 years ago
 Satish   speed = 25km/h & distance=105km 5 years ago
 Shubham Gupta   Velocity = 25km/h and dist = 105km 4 years ago