Three men shot the same target. The probability of the first, second and the third man hitting the target respectively is 0.3, 0.5 and 0.6. Find the probability that exactly one of them hits the target.
A:0.41
B:0.6
C:0.5
D:0.7
Answer: A

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    A 0.3*(1-0.5)*(1-0.6) + (1-0.3)*0.5*(1-0.6) + (1-0.3)*(1-0.5)*0.6 = 0.41






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    A please give me the solution of this problem.


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    A please solve this problem.



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    A please solve this problem.




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