There are four dogs, each at the counter of a large square. Each of the dogs begins chasing the dog clockwise from it. All of the dogs run at the same speed. All continuously adjust their direction so that they are always heading straight towards their clockwise neighbor. How long does it take for the dogs to catch each other? Where does this happen? (Hint: Dog’s are moving in a symmetrical fashion, not along the edges of the square).
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    A sandeep is correct see relative velocity if any two dogs







    Smiley

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    A let the initial size of the square be =x it is given dat speed of the dogs is =v then dey will meet at the centre in time t=x/v ...consider ny two dogs A nd B wid A chasing B then at ny instant velocity of B is perpendicular to the distance vector b/w the two dogs so it is nt effectin the distance b/w dem it is only A's velocity which makes d difference nd it is always in the direction of the distance vector b/w A&B as given. thanku.


    Smiley

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    A i know about where it happens not the time...they meet in the centre since they r moving in a spiral towards the centre


    Smiley
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