You are given an array containing positive integers. All the integers occur even number of times except one. Find this special integer. Click for Solution |
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A void main()
{
int a[10][2],flag=0,n=0;
int arr[]={2,3,6,7,2,3,3,3,3,7,7,3,6,6,6};
for(int i=0;i<10;i++)
a[i][1]=0;
for(int i=0;i<15;i++)
{
for(int j=0;j<n;j++)
{
if(a[j][0]==arr[i])
{
flag=1;
a[j][1]++;
break;
}
}
if(flag==0)
{
a[n][0]=arr[i];
a[n][1]=1;
n++;
}
flag=0;
}
for(int i=0;i<10;i++)
{
if(a[i][1]%2!=0)
{
cout<<a[i][0];
break;
}
}
}
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