Five questions are based on the matrix given below:-
T K Y L M
K R Z N K
S L M B Z
I P L F N
F Q K Z B
Q. No. :
1
Question :
Replace column(2) by row(2), then column(4) by row(4) followed by column(2) by column(4), then the element at position (5 x 4) is
A :
K
B :
N
C :
F
D :
Z
Answer: A
Q. No. :
2
Question :
Replace column(1) by column(3) , then row(3) by row(5) then the element above the vowel is?
A :
K
B :
F
C :
S
D :
N
Answer: B
Q. No. :
3
Question :
Replace row(2) by row(5) then column(3) by column(5), followed by row(5) by row(3), then the element at position (3 x 4) is
A :
F
B :
B
C :
Z
D :
N
Answer: D
Q. No. :
4
Question :
If we reverse the element from top left to bottom right and then top right to bottom left, then the element at position (4 x 3) is
A :
L
B :
F
C :
B
D :
N
Answer: C
Q. No. :
5
Question :
If Z=5, K=2 and N=1; If the sum of all the numbers in the matrix is divisible by 3 then replace row(1) by row(4) and column(4) by column(2), If it is divisible by 4 then replace row(2) by row(5) then column(5) by column(2). After the whole process find the position of the element at (3 x 2)?
A :
M
B :
L
C :
K
D :
Z
Answer: D
Solve the following question using the matrix shown below:-
{a b c d
e f g h
i j k l
m n o p}
Q. No. :
6
Question :
Exchange the row(2) by col(2) then the row(2) by row(4) then row(4) by col(4), the element at the position (4 x 3) is
Step 1.
Exchange the row(2) by col(2) a e c d
b f j n
i g k l
m h o p Step 2. Exchange the row(4) by col(4) a e c m
b f j h
i g k o
d n l p element at the position (4 x 3) is l
Q. No. :
7
Question :
In the above question change the row(3) by column(3), then the element at (3 x 2) is
Given Matrix: a b c d e f g h i j k l m n o p Change the row(3) by column(3) : a b i d e f j h c g k o m n l p Element at (3x2) is g
Q. No. :
8
Question :
Change all the rows by the column of same numbers, and doing the same by keeping the element d fixed for the next, then the element at position (3 x 3) is
Change all the rows by the column of same numbers = Transposing the matrix by keeping 'a' fixed= a e i m b f j n c g k o d h l p
Now we will transpose by keeping 'd' fixed p o n m l k j i h g f e d c b a
so element at 3x3=f
Q. No. :
9
Question :
Change the column(2) by row(2) and then row(3) by row(2) then what is the element at (3 x 2).
A :
e
B :
b
C :
f
D :
j
Answer: C
Q. No. :
10
Question :
Change the row(3) by column(3) then what is the element at position (3 x 3)
A :
g
B :
c
C :
j
D :
k
Answer: D
Five questions are based on the matrix given below:-
@ % $ # )
% + # & ^
@ & % # !
* + $ & %
/ ^ ! + $
Q. No. :
11
Question :
If number of occurrence of % is more than $ then replace row(2) by row(5) followed by column(3) by column(5). If it is less then $ then replace row(3) by row(5), then column(2) by column(4). After the whole process the element at position (4 x 3) is
A :
%
B :
$
C :
&
D :
#
Answer: A
Q. No. :
12
Question :
If we diagonally change the matrix from top right to bottom left by keeping $ fixed(they cannot change their position), then the element at position (2 x 3) is
A :
+
B :
$
C :
#
D :
%
Answer: C
Q. No. :
13
Question :
Replace row(2) by row(5), then column(2) by column(4). Find the element at position (3 x 4)
A :
%
B :
&
C :
#
D :
@
Answer: B
Q. No. :
14
Question :
Change all the rows with equal number of column (in the increasing order), by keeping # fixed(i.e they cannot change position with other element), then find the element at position (3 x 2)
A :
+
B :
%
C :
#
D :
&
Answer: D
Q. No. :
15
Question :
Replace all '+' by 1, '@' by 2 and '%' sign by 3. If the sum of numbers of the matrix is odd replace row(2) by row(4) and find (2 x 5). If sum is even replace column(2) by column(4) and find (4 x 4).
A :
+
B :
&
C :
^
D :
%
Answer: D
Five questions are based on the matrix given below:-
# 8 @ ? $
k * Z + 8
S ? $ 2 Z
I P ? F +
F Q 8 Z 2
Q. No. :
16
Question :
Reverse the element from top left to bottom right and then top right to bottom left, find the element at position (4 x 3)
A :
?
B :
F
C :
2
D :
+
Answer: C
Q. No. :
17
Question :
Replace row(2) by row(5) then column(3) by column(5) followed by row(5) by row(3), then the element at position (3 x 4) is
A :
F
B :
2
C :
Z
D :
+
Answer: D
Q. No. :
18
Question :
Replace column(1) by column(3) then row(3) by row(5) then the element above the vowel is?
A :
K
B :
F
C :
S
D :
+
Answer: B
Q. No. :
19
Question :
If sum of all the numbers in the matrix is divisible by 3 then replace row(1) by row(4) then column(4) by column(2). If it is divisible by 4 then replace row(2) by row(5) then column(5) by column(2). After the process find the element at the position (3 x 2)
A :
$
B :
?
C :
8
D :
Z
Answer: D
Q. No. :
20
Question :
Replace Column(2) by row(2) then column(4) by row(4), followed by column(2) by column(4), then the element at (5 x 4) is
A :
8
B :
+
C :
F
D :
Z
Answer: A
Five questions are based on the matrix given below:-
@ % # ! ?
) + ? * )
+ * ) > <
/ ) ? ( (
) - # @ =
Q. No. :
21
Question :
What is the element that is left to the element that is below the element in row four column 4.
A :
-
B :
)
C :
(
D :
#
Answer: D
Q. No. :
22
Question :
If all the rows and column are interchanged(one by one in increasing order) then what is the third element of row five.
A :
(
B :
>
C :
<
D :
*
Answer: C
Q. No. :
23
Question :
Replace column(5) by column(2) then row(2) by row(5) followed by column(1) by column(4) then the element at the position (5 x 4) is
A :
*
B :
)
C :
?
D :
(
Answer: B
Q. No. :
24
Question :
Let '*'= 1, '?'=2, '!'=3, '<'=9 and '('=7 If the sum of all the numbers is even then reverse the element (from top left to bottom right), if it is odd then reverse the element (from bottom left to top right). Find the element at the position (3 x 2).
A :
>
B :
?
C :
)
D :
*
Answer: B
Q. No. :
25
Question :
Replace row(2) by row(4), then column(3) by column(1). Find the element at position (4 x 3).
The regular hexagon of side 2m, inside which a circle is drawn by touching all its side. Find the area of the circle.
A :
pie
B :
2*pie
C :
3*pie
D :
pie/2
Answer: C
Q. No. :
2
Question :
A set of 7 pens, 9 erasers and 11 sharpeners costs Rs 79 and 2 pens, 5 erasers and 8 sharpeners cost Rs 42. Find the total cost of one sharpeners, one eraser and one pen.
A :
Rs 9
B :
Rs 10
C :
Rs 11
D :
Rs 12
Answer: A
Q. No. :
3
Question :
A is thrice as good a workman as B and so takes 60 days less than B for doing a job. Find the time in which they can do it together.
A :
20 days
B :
43/2 days
C :
45/2 days
D :
95/4 days
Answer: C
Q. No. :
4
Question :
A sphere is cut into 4 identical pieces after it was painted. What is the ratio of the painted area to the unpainted area?
A :
1:1
B :
1:2
C :
2:3
D :
3:2
Answer: A
Q. No. :
5
Question :
The average age of a committee of seven trustees is the same as it was five years ago, a younger man having been substituted for one of them. How much younger was he than the trustee whose place he took?
Let the average age be x Sum of ages = 7x Sum of ages of previous members five year ago = 7x - (y+5) + z - 30 where y and z are ages of new and substituted member 5 years ago. 7x = 7x - y + z -35 or, z - y = 35