Study the following information and answer the question that follow ::
Five people joined different engineering colleges. Their first names were Sarah (Ms.), Swati (Ms.), Jackie, Mohan and Priya (Ms.). The surnames were Reddy, Gupta. Sanyal, Kumar and Chatterjee. Except for one college which was rated as 3 star, all other colleges were rated either 4 star or 5 star.
The “Techno Institute” had a higher rating than the college where Priya studied. The three-star college was not “Deccan College.” Mohan’s last name was Gupta but the didn’t study at “Barla College.” Sarah, whose last name wasn’t Sanyal, joined “Techno Institute.” Ms. Kumar and Jackie both studied at four-star colleges. Ms. Reddy studied at the “Anipal Institute,” which wasn’t five-star college. The “Barla College” was a five-star college. Swati’s last name wasn’t Chatterjee. The “Chemical College” was rated with one star less than the college where Sanyal studied. Only one college was rated five star.
Answer: D According to the given data provided in the question, direct inferences
that can be made are: 1. Only one college was rated as 3-star
and one as five star. 2. Barla college was rated as
5-star. It is also given that Ms. Reddy joined 'Anipal
Institute' Since, Sarah(Ms.) joined at 'Techno institute',
Mohan and Jackie are not Ms. So either Priya or Swati has to be Reddy.
Also, Mohan cannot study in Techno, Anipal or Barla. So, he joined
either Deccan or Chemical. It is given that Ms. Kumar and
Jackie joined a 4-star college and Swati's last name was not Chatterjee.
Chemical college had a rating one less than that of the college where
Sanyal joined. So, it has to be either a 3-star or a 4-star college. But
Mohan joined Deccan or Chemical, a 4-star. Barla is a 5-star. Deccan,
Techno and Chemical are 4-stars. So Anipal is a 3-star and
Priya Reddy joined Anipal. Sanyal joined a 5-star rated college, so
Swati should have joined there. Based on the inferences, the following
table can be formed:
Answer: A According to the given data provided in the question, direct inferences
that can be made are: 1. Only one college was rated as 3-star
and one as five star. 2. Barla college was rated as
5-star. It is also given that Ms. Reddy joined 'Anipal
Institute' Since, Sarah(Ms.) joined at 'Techno institute',
Mohan and Jackie are not Ms. So either Priya or Swati has to be Reddy.
Also, Mohan cannot study in Techno, Anipal or Barla. So, he joined
either Deccan or Chemical. It is given that Ms. Kumar and
Jackie joined a 4-star college and Swati's last name was not Chatterjee.
Chemical college had a rating one less than that of the college where
Sanyal joined. So, it has to be either a 3-star or a 4-star college. But
Mohan joined Deccan or Chemical, a 4-star. Barla is a 5-star. Deccan,
Techno and Chemical are 4-stars. So Anipal is a 3-star and
Priya Reddy joined Anipal. Sanyal joined a 5-star rated college, so
Swati should have joined there. Based on the inferences, the following
table can be formed:
Answer: B According to the given data provided in the question, direct inferences
that can be made are: 1. Only one college was rated as 3-star
and one as five star. 2. Barla college was rated as
5-star. It is also given that Ms. Reddy joined 'Anipal
Institute' Since, Sarah(Ms.) joined at 'Techno institute',
Mohan and Jackie are not Ms. So either Priya or Swati has to be Reddy.
Also, Mohan cannot study in Techno, Anipal or Barla. So, he joined
either Deccan or Chemical. It is given that Ms. Kumar and
Jackie joined a 4-star college and Swati's last name was not Chatterjee.
Chemical college had a rating one less than that of the college where
Sanyal joined. So, it has to be either a 3-star or a 4-star college. But
Mohan joined Deccan or Chemical, a 4-star. Barla is a 5-star. Deccan,
Techno and Chemical are 4-stars. So Anipal is a 3-star and
Priya Reddy joined Anipal. Sanyal joined a 5-star rated college, so
Swati should have joined there. Based on the inferences, the following
table can be formed:
Name(Sex)
Surname
College
Rating (In
star)
Saraf (F)
Kumar
Techno
4
Swati (F)
Sanyal
Barla
5
Jackie (M)
Chatterjee
Deccan
4
Mohan (M)
Gupta
Chemical
4
Priya (F)
Reddy
Anipal
3
Q. No. 4:
Which is the correct combination of first names and surnames?
Answer: D According to the given data provided in the question, direct inferences
that can be made are: 1. Only one college was rated as 3-star
and one as five star. 2. Barla college was rated as
5-star. It is also given that Ms. Reddy joined 'Anipal
Institute' Since, Sarah(Ms.) joined at 'Techno institute',
Mohan and Jackie are not Ms. So either Priya or Swati has to be Reddy.
Also, Mohan cannot study in Techno, Anipal or Barla. So, he joined
either Deccan or Chemical. It is given that Ms. Kumar and
Jackie joined a 4-star college and Swati's last name was not Chatterjee.
Chemical college had a rating one less than that of the college where
Sanyal joined. So, it has to be either a 3-star or a 4-star college. But
Mohan joined Deccan or Chemical, a 4-star. Barla is a 5-star. Deccan,
Techno and Chemical are 4-stars. So Anipal is a 3-star and
Priya Reddy joined Anipal. Sanyal joined a 5-star rated college, so
Swati should have joined there. Based on the inferences, the following
table can be formed:
Name(Sex)
Surname
College
Rating (In
star)
Saraf (F)
Kumar
Techno
4
Swati (F)
Sanyal
Barla
5
Jackie (M)
Chatterjee
Deccan
4
Mohan (M)
Gupta
Chemical
4
Priya (F)
Reddy
Anipal
3
Q. No. 5:
Which option gives a possible student – Institute combination?
Answer: B According to the given data provided in the question, direct inferences
that can be made are: 1. Only one college was rated as 3-star
and one as five star. 2. Barla college was rated as
5-star. It is also given that Ms. Reddy joined 'Anipal
Institute' Since, Sarah(Ms.) joined at 'Techno institute',
Mohan and Jackie are not Ms. So either Priya or Swati has to be Reddy.
Also, Mohan cannot study in Techno, Anipal or Barla. So, he joined
either Deccan or Chemical. It is given that Ms. Kumar and
Jackie joined a 4-star college and Swati's last name was not Chatterjee.
Chemical college had a rating one less than that of the college where
Sanyal joined. So, it has to be either a 3-star or a 4-star college. But
Mohan joined Deccan or Chemical, a 4-star. Barla is a 5-star. Deccan,
Techno and Chemical are 4-stars. So Anipal is a 3-star and
Priya Reddy joined Anipal. Sanyal joined a 5-star rated college, so
Swati should have joined there. Based on the inferences, the following
table can be formed:
Name(Sex)
Surname
College
Rating (In
star)
Saraf (F)
Kumar
Techno
4
Swati (F)
Sanyal
Barla
5
Jackie (M)
Chatterjee
Deccan
4
Mohan (M)
Gupta
Chemical
4
Priya (F)
Reddy
Anipal
3
Study the following information and answer the question that follow ::
A circular field, with inner radius of 10 meters and outer radius of 20 meters, was divided into five successive stages for ploughing. The ploughing of each stages was handed over to a different farmer. 1. Farmers are referred to by following symbols: F1, F2, F3, F4, F5. 2. The points between different stages of project are referred to by the following symbols: P1, P2, P3, P4, P5, not necessarily in the order. 3. Farmer F5 was given the work of ploughing stage starting at point P4. 4. The stage from point P5 to point P3 was not the first stage. 5. Farmer F4 was given the work of the fourth stage. 6. Stage 3 finished at point P1, and the work of which was not given to farmer F1. 7. Farmer F3 was given work of stage ending at point P5.
Answer: D Stage 3 finished at point P1 and the work in the stage 4 was done by
F4. It is given that one of the stage starts with P5 and ends
with P3, and that stage cannot be the stage 1 (Condition 4), stage 3
(Condition 6), stage 4 (Condition 6) or stage 5 (Condition
4). Hence, stage 2 starts and ends with point P5 and P3
respectively. Therefore, F3 has ploughed in stage 1 (Condition
7). So stage 5 will start and end with P4 and P2 respectively
(Condition 3) So the work of stage 2 and stage 3 will be done
by F1 and F2 respectively (Condition 6). Based on the
inferences, the following table can be
formed:
Stage
Starting Point
End Point
Farmer
1
P2
P5
F3
2
P5
P3
F1
3
P3
P1
F2
4
P1
P4
F4
5
P4
P2
F5
Q. No. 2:
Which were the starting and finish points of stage 2?
Answer: B Stage 3 finished at point P1 and the work in the stage 4 was done by
F4. It is given that one of the stage starts with P5 and ends
with P3, and that stage cannot be the stage 1 (Condition 4), stage 3
(Condition 6), stage 4 (Condition 6) or stage 5 (Condition
4). Hence, stage 2 starts and ends with point P5 and P3
respectively. Therefore, F3 has ploughed in stage 1 (Condition
7). So stage 5 will start and end with P4 and P2 respectively
(Condition 3) So the work of stage 2 and stage 3 will be done
by F1 and F2 respectively (Condition 6). Based on the
inferences, the following table can be
formed:
Answer: A Stage 3 finished at point P1 and the work in the stage 4 was done by
F4. It is given that one of the stage starts with P5 and ends
with P3, and that stage cannot be the stage 1 (Condition 4), stage 3
(Condition 6), stage 4 (Condition 6) or stage 5 (Condition
4). Hence, stage 2 starts and ends with point P5 and P3
respectively. Therefore, F3 has ploughed in stage 1 (Condition
7). So stage 5 will start and end with P4 and P2 respectively
(Condition 3) So the work of stage 2 and stage 3 will be done
by F1 and F2 respectively (Condition 6). Based on the
inferences, the following table can be
formed:
Answer: A Stage 3 finished at point P1 and the work in the stage 4 was done by
F4. It is given that one of the stage starts with P5 and ends
with P3, and that stage cannot be the stage 1 (Condition 4), stage 3
(Condition 6), stage 4 (Condition 6) or stage 5 (Condition
4). Hence, stage 2 starts and ends with point P5 and P3
respectively. Therefore, F3 has ploughed in stage 1 (Condition
7). So stage 5 will start and end with P4 and P2 respectively
(Condition 3) So the work of stage 2 and stage 3 will be done
by F1 and F2 respectively (Condition 6). Based on the
inferences, the following table can be
formed:
Answer: D Stage 3 finished at point P1 and the work in the stage 4 was done by
F4. It is given that one of the stage starts with P5 and ends
with P3, and that stage cannot be the stage 1 (Condition 4), stage 3
(Condition 6), stage 4 (Condition 6) or stage 5 (Condition
4). Hence, stage 2 starts and ends with point P5 and P3
respectively. Therefore, F3 has ploughed in stage 1 (Condition
7). So stage 5 will start and end with P4 and P2 respectively
(Condition 3) So the work of stage 2 and stage 3 will be done
by F1 and F2 respectively (Condition 6). Based on the
inferences, the following table can be
formed:
Stage
Starting Point
End Point
Farmer
1
P2
P5
F3
2
P5
P3
F1
3
P3
P1
F2
4
P1
P4
F4
5
P4
P2
F5
Study the following information and answer the questions that follow ::
Six states having equal area in a country are located in North-South directions in two columns next to each other. States are located in the given order, State 1, State 3, and State 5 are on the western side and State 2, State 4, and State 6 are on the eastern side. Within the six states, there are on the eastern side. Within the six states, there are exactly four medical institutes, two management institutes, and two technical institutes. These eight institutions are located as follows. 1). No institutions is in more than one of the states. 2). None of the states contains more than one management institute, and none contains more than one technical institute. 3). None of the states contains both a management institute and a technical institute. 4). Each management institute is located in a state that contains at least one medical institute. 5). The technical institute are located in two states that do not share a common boundary. 6). State 3 contains a technical institute, and state 6 contains a management institute.
Answer: D For the given question, we can draw the following diagram and conclusions. (i) State 3 contains technical Institute and state 6 contains a management Institute. State 6 cannot contain a technical institute and also state 1, 4 and 5 cannot contain a technical institute as they share the common boundary. Therefore state 2 contains a technical institute. (ii) State 6 will contain at least one medical institute. Since only four medical institutes are given and none of the states can contain more than one institute, therefore available sates for medical institutes are 1, 4, 5, 6.
Q. No. 2:
A complete and accurate list of the states, any one of which could contain the management institute that is not in State 6, would be ________.
Answer: C For the given question, we can draw the following diagram and
conclusions. (i) State 3
contains technical Institute and state 6 contains a management
Institute. State 6 cannot contain a technical institute and also state
1, 4 and 5 cannot contain a technical institute as they share the common
boundary. Therefore state 2 contains a technical
institute. (ii) State 6 will contain at least one medical
institute. Since only four medical institutes are given and none of the
states can contain more than one institute, therefore available sates
for medical institutes are 1, 4, 5, 6.
Q. No. 3:
If each of the six states contains at least one of the eight institutions, then which one of the following must be true?
Answer: D For the given question, we can draw the following diagram and
conclusions. (i) State 3
contains technical Institute and state 6 contains a management
Institute. State 6 cannot contain a technical institute and also state
1, 4 and 5 cannot contain a technical institute as they share the common
boundary. Therefore state 2 contains a technical
institute. (ii) State 6 will contain at least one medical
institute. Since only four medical institutes are given and none of the
states can contain more than one institute, therefore available sates
for medical institutes are 1, 4, 5, 6.
Q. No. 4:
If one of the states contains exactly two medical institutes and exactly one technical institute, then which combinational of three states might contain no medical institute?
Answer: D For the given question, we can draw the following diagram and
conclusions. (i) State 3
contains technical Institute and state 6 contains a management
Institute. State 6 cannot contain a technical institute and also state
1, 4 and 5 cannot contain a technical institute as they share the common
boundary. Therefore state 2 contains a technical
institute. (ii) State 6 will contain at least one medical
institute. Since only four medical institutes are given and none of the
states can contain more than one institute, therefore available sates
for medical institutes are 1, 4, 5, 6.
Study the following information and answer the questions that follow ::
Seven film buffs—Gangadhar, Indra, Lalatakshaya, Maheshwar, Rudra, Vyomkesha, and Yogi—attend a showing of classic films. Three films are shown: one each directed by Guru Dutt, Satyajit Ray, and Ritwik Ghatak. Each of the film buffs sees exactly one of the three films. The films are shown only once, one film at a time. The following restrictions apply: 1) Exactly twice as many of the film buffs see the Satyajit Ray film as see the Guru Dutt film. 2) Gangadhar and Rudra do not see the same film as each other. 3) Indra and Maheshwar do not see the same film as each other. 4) Vyomkesha and Yogi see the same film as each other. 5) Lalatakshaya sees the Satyajit Ray film. 6) Gangadhar sees either the Guru Dutt film or the Ritwik Ghatak film.
Q. No. 1:
Which one of the following could be an accurate matching of film buffs to films?
A :
Gangadhar: the Satvajit Rav film; Indra: the Ritwik Ghatak film; Maheshwar: the Satyajit Ray film
B :
Gangadhar: the Ritwik Ghatak film; Indra: the Guru Dutt film; Vyomkesha: the Guru Dutt film
C :
Indra: the Satyajit Ray film; Rudra: the Ritwik Ghatak film; Vyomkesha: the Guru Dutt film
D :
Maheshwar: the Ritwik Ghatak film; Rudra: the Ritwik Ghatak film; Vyomkesha: the Ritwik Ghatak film
Answer: D On the basis of information we have some hints 1). If GD is shown by 1 than SR by 2 and RG by 4. If GD is shown by 2 than SR by 4 and RG by 1. Conclusion : a). GD is shown by either 1 or 2. b). SR is shown by either 2 or 4. c). RG is shown by either 4 or 1. 2). Gan and Rud -> do not see same film Ind, Mah -> do not see same film Vyo and Yo -> see the same film 3). Lal sees only SR films 4). Gan sees either GD or RG films (Not SR films). => Option A is wrong because Gan does not see SR films. Option B is wrong because 3 person (Ind, Vyo and Yo) cannot see GD film. Option C is wrong because if Vyo and Yo see GD films then SR film will be showm by 4 person (Lal, Ind, Mah and Rud) and (Ind, Mah) does not see the same film.
Q. No. 2:
Each of the following must be false EXCEPT:
A :
Rudra is the only film buff to see the Guru Dutt film.
B :
Rudra is the only film buff to see the Satyajit Ray film.
C :
Yogi is the only film buff to see the Ritwik Ghatak film.
D :
Exactly two film buffs see the Ritwik Ghatak film.
Answer: A On the basis of information we have some hints
1). If GD is shown by 1 than SR by 2 and RG by 4.
If GD is shown by 2 than SR by 4 and RG by 1.
Conclusion :
a). GD is shown by either 1 or 2.
b). SR is shown by either 2 or 4.
c). RG is shown by either 4 or 1.
2). Gan and Rud -> do not see same film
Ind, Mah -> do not see same film
Vyo and Yo -> see the same film
3). Lal sees only SR films
4). Gan sees either GD or RG films (Not SR films). => Option B is wrong because Lal always see SR films. Option C is wrong because if Yo sees RG films then Vyo see RG films. Option D is wrong because RG is shown by either 1 or 2 buffs.
Q. No. 3:
Which one of the following could be a complete and accurate list of the film buffs who DO NOT see the Satyajit Ray film?
Answer: C On the basis of information we have some hints
1). If GD is shown by 1 than SR by 2 and RG by 4.
If GD is shown by 2 than SR by 4 and RG by 1.
Conclusion :
a). GD is shown by either 1 or 2.
b). SR is shown by either 2 or 4.
c). RG is shown by either 4 or 1.
2). Gan and Rud -> do not see same film
Ind, Mah -> do not see same film
Vyo and Yo -> see the same film
3). Lal sees only SR films
4). Gan sees either GD or RG films (Not SR films). => We consider the following based on information, Option A and B -> Gan - GD/RG , Rud - RG/GD, Lal-SR, Mah-RG, Vyo-RG, Yo-RG Option D -> Gan - GD/RG, Rud-RG/GD, Lal-SR, Ind-SR, Mah-RG, Vyo-RG, Yo-RG Option C -> Gan- GD/RG, Rud-RG/GD, Lal-SR, Ind-GD, Mah-SR, Vyo-SR, Yo-SR Hence, only option C is complete and accurate.
Q. No. 4:
If exactly one film buff sees the Ritwik Ghatak film, then which one of the following must be true?
Answer: A On the basis of information we have some hints
1). If GD is shown by 1 than SR by 2 and RG by 4.
If GD is shown by 2 than SR by 4 and RG by 1.
Conclusion :
a). GD is shown by either 1 or 2.
b). SR is shown by either 2 or 4.
c). RG is shown by either 4 or 1.
2). Gan and Rud -> do not see same film
Ind, Mah -> do not see same film
Vyo and Yo -> see the same film
3). Lal sees only SR films
4). Gan sees either GD or RG films (Not SR films). => If 1 film buff sees RG films than 2 buffs will see GD film and 4 buffs will see RG films. Considering this we get, Gan -GD/RG Rud- RG/GD Lal-SR Ind-GD/SR Mah-SR/GD Vyo-SR Yo-SR
Q. No. 5:
If Vyomkesha and Gangadhar see the same film, then which one of the following could be true?
Answer: B On the basis of information we have some hints
1). If GD is shown by 1 than SR by 2 and RG by 4.
If GD is shown by 2 than SR by 4 and RG by 1.
Conclusion :
a). GD is shown by either 1 or 2.
b). SR is shown by either 2 or 4.
c). RG is shown by either 4 or 1.
2). Gan and Rud -> do not see same film
Ind, Mah -> do not see same film
Vyo and Yo -> see the same film
3). Lal sees only SR films
4). Gan sees either GD or RG films (Not SR films). =>Option A is wrong because, Gan, Vyo and Yo Can not see GD films. Option C is wrong because if Rud see RG film than Gan will see GD film and same as Option A 3 buffs cannot see GD films. Option D is wrong because Gan does not see SR films.
Q. No. 6:
Each of the following could be a complete and accurate list of the film buffs who see the Guru Dutt film EXCEPT:
Answer: D On the basis of information we have some hints
1). If GD is shown by 1 than SR by 2 and RG by 4.
If GD is shown by 2 than SR by 4 and RG by 1.
Conclusion :
a). GD is shown by either 1 or 2.
b). SR is shown by either 2 or 4.
c). RG is shown by either 4 or 1.
2). Gan and Rud -> do not see same film
Ind, Mah -> do not see same film
Vyo and Yo -> see the same film
3). Lal sees only SR films
4). Gan sees either GD or RG films (Not SR films). => Vyo and Yo cannot see GD films because if they see GD films than SR will see by 4 buffs, i.e Rud, Lal, Ind and Mah. And, Mah and Ind -> do not see the same film.
Study the following information and answer the questions that follow ::
Krishnapuram’s town council has exactly three members: Arjun, Karn, and Bhim. During one week, the council members vote on exactly three bills: a recreation bill, a school bill, and a tax bill. Each council member votes either for or against each bill. The following is known: 1) Each member of the council votes for at least one of the bills and against at least one of the bills. 2) Exactly two members of the council vote for the recreation bill. 3) Exactly one member of the council votes for the school bill. 4) Exactly one member of the council votes for the tax bill. 5) Arjun votes for the recreation bill and against the school bill. 6) Karn votes against the recreation bill. 7) Bhim votes against the tax bill.
Q. No. 1:
Which one of the following statements could be true?
A :
Arjun and Karn vote the same way on the tax bill.
B :
Karn and Bhim vote the same way on the recreation bill.
C :
Karn and Bhim vote the same way on the school bill.
D :
Arjun votes for one of the bills and Karn votes for two of the bills.
Answer: D On the basis of the information we get some hints Vote for Rec =
2 members Vote for Tax = 1 members Vote for Sch.= 1
or 2.
Bill
For
Against
Rec
A and B
K
Sch
K/B/K and B
A and K/B/K and B
Tax
K/A
B and K/A
From the main table, we find the following two table
::
Bill
For
Against
Rec
A and B
K
Sch
K
A and B
Tax
K
A and B
Bill
For
Against
Rec
A and B
K
Sch
B
A and K
Tax
K
B and A
From table number -1.
Q. No. 2:
If the set of members of the council who vote against the school bill are the only ones who also vote against the tax bill, then which one of the following statements must be true?
Answer: C On the basis of the information we get some hints Vote for Rec =
2 members Vote for Tax = 1 members Vote for Sch.= 1
or 2.
Bill
For
Against
Rec
A and B
K
Sch
K/B/K and B
A and K/B/K and B
Tax
K/A
B and K/A
From the main table, we find the following two table
::
Bill
For
Against
Rec
A and B
K
Sch
K
A and B
Tax
K
A and B
Bill
For
Against
Rec
A and B
K
Sch
B
A and K
Tax
K
B and A
From table number -1.
Q. No. 5:
If one of the members of the council votes against exactly the same bills as does another member of the council, then which one of the following statements must be true?
Answer: D On the basis of the information we get some hints Vote for Rec =
2 members Vote for Tax = 1 members Vote for Sch.= 1
or 2.
Bill
For
Against
Rec
A and B
K
Sch
K/B/K and B
A and K/B/K and B
Tax
K/A
B and K/A
From the main table, we find the following two table
::
Bill
For
Against
Rec
A and B
K
Sch
K
A and B
Tax
K
A and B
Bill
For
Against
Rec
A and B
K
Sch
B
A and K
Tax
K
B and A
From table number-1.
Study the following information and answer the questions that follow ::
In a local pet store, seven puppies wait to be introduced to their new owners. The puppies, named Ashlen, Blakely, Custard, Daffy, Earl, Fala and Gabino, are all kept in two available pens. Pen 1 holds three puppies, and pen 2 holds four puppies. 1). If Gabino is kept in pen 1, then Daffy is not kept in pen 2. 2). If Daffy is not kept in pen 2, then Gabino is kept in pen 1. 3). If Ashlen is kept in pen 2, then Blakely is not kept in pen 2. 4). If Blakely is kept in pen 1, then Ashlen is not kept in pen 1.
Q. No. 1:
Which of the following groups of puppies could be in pen 2?
Answer: D Option A: The given group of puppies cannot be in pen 2 as Blakely and Ashley cannot be together in pen 1. Option B: The given group of puppies cannot be in pen 2 as Blakely and Ashlen cannot be together in pen 2. Option C: The given group of puppies cannot be in pen 2 as if Daffy is not kept in pen 2, then Gabino is kept in pen 1 and in this case Gabino is put in pen 2. Option D: The given group of puppies can be in pen 2.
Q. No. 2:
If Earl shares a pen with Fala, then which of the following MUST be true?
Answer: B Given that Earl shares a pen with Fala. Option A is not necessarily true as: The puppies in pen 1 could be Earl, Fala and Blakely. The puppies in pen 2 could be Gabino, Daffy, Ashlen and Custard. Option B is necessarily true as Gabino and Daffy have to be together and given that Earl and Fala are also together. Also, Ashlen and Blakely have to be in different pens. So, Custard must be in pen 2, which has four puppies. Option C is not necessarily true as: The puppies in pen 1 could be Gabino, Daffy and Ashlen. The puppies in pen 2 could be Earl, Fala, Custard and Blakely. Option D is not necessarily true as: The puppies in pen 1 could be Gabino, Daffy and Ashlen. The puppies in pen 2 could be Earl, Fala, Custard and Blakely.
Q. No. 3:
If Earl and Fala are in different pens, then which of the following must NOT be true?
Answer: D Given that Earl and Fala are in different pens. Option A can be true as: The puppies in pen 2 could be Earl, Gabino, Daffy and Ashlen. The puppies in pen 1could be Fala, Custard and Blakely. Option B can be true as: The puppies in pen 2could be Fala, Gabino, Daffy and Ashlen. The puppies in pen 1 could be Earl, Custard and Blakely. Option C can be true as: The puppies in pen 2 could be Earl, Gabino, Daffy and Blakely The puppies in pen 1 could be Fala, Custard and Ashlen. Option D cannot be true as it means Custard is in pen 2 and Fala is in pen 1. So, Earl is in pen 2 along with Custard. Daffy and Blakely have to be in different pens. But Gabino and Daffy have to be together. Hence this cannot be true.