The compound interest accured on an amount of Rs 25,000 at the end of four years is Rs 5387.65625. What would be the simple interest accured on the same amount at the same rate in the same period ?
Answer: B CI = P{(1 +r/100)3 -1 } => P {(1 + 15/100)3 -1} = 9844.5375 => P[1.520875 -1] = 9844.5375 P = Rs 18,900.
Q. No. 46:
A part of rs 9600 is invested at a 5% annual return, while the remainder is invested at a 3% annual return. If the annual income from both portions is the same, what is the total income from the two investments ?
Answer: C Let the annual amount investment at 5% and 3% be Rs x and Rs (9600-x) respectively. Then, (x*5*1)/100 = [(9600-x)*3*1]/100 => x = Rs 3600. So, total income = (3600*5*1)/100 + [(9600-3600)*3*1]/100 => 180 + 180 = Rs 360.
Q. No. 47:
What would be the compound interest accrued on an amount of Rs 8400 at the rate of 12.5% per annum at the end of 3 years ? (Rounded off two digits after decimal).
Answer: C CI = P(1+ r/100)t - P => 8400(1 + 12.5/100)3 - 8400 => 8400 (1 + 1/8)3 - 8400 => 8400 [729/512 - 1] => 113925/32 => 3560.16.
Q. No. 48:
To start a new enterprise, Mr. Yogesh has borrowed a total of Rs 60,000 from two money lenders with the interest being compounded annually, to be repaid at the end of 2 year. Mr. Yogesh repaid Rs 38,800 more to the first money lender compared to the second money lender at the end of 2 year. The first money lender charged an interest rate, which was 10% more than what was charged by the second money lender. If Mr. Yogesh had instead borrowed Rs 30,000 from each at their respective initial rates for 2 years, he would have paid Rs 7500 more to the first money lender compared to the second. Then, money borrowed by Mr. Yogesh from first money lender is :
Answer: C If the rate of interest changed by the second part is r%. Then, on the first it is (r+10)%. 30,000[1 + (r+10)/100]2 - 30000[1 + r/100]2 = 7500 r = 20% Let the first part be x , then the second part will be 60,000-x x[1 + 30/100]2 - (60,000-x)[1 + 20/100]2 = 38,800 => x = 40,000.