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13.
The input voltage given to a converter is
Vi = 100√2 sin(100πt) V
The current drawn by the converter is
Ii = 10√2sin(100πt-π/3) + 5√2sin(300πt+π/4) + 2√2sin(500πt-π/6) A
[1] The input power factor of the converter is [2 marks]
(A) 0.31
(B) 0.44
(C) 0.5
(D) 0.71[2] The active power drawn by the converter is [2 marks]
(A) 181 W
(B) 500 W
(C) 707 W
(D) 887 Wasked in Electrical Engineering, 2011
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14.
An RLC circuit with relevant data is given below.
[1] The power dissipated in the resistor R is [2 marks]
(A) 0.5 W
(B) 1 W
(C) √2W
(D) 2 W[2] The current Ic in the figure above is [2 marks]
(A) –j2 A
(B) –j1/√2 A
(C) +j1/√2 A
(D) +j2 Alast reply by CpjJwWHV • 13 years ago • asked in Electrical Engineering, 2011
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last reply by CpjJwWHV • 13 years ago • asked in Electrical Engineering, 2011
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18.
is decomposed into a product of a lower triangular matrix [L] and an upper triangular matrix [U]. The properly decomposed [L] and [U] matrices respectively are [2 marks]