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655.

The time domain behavior of a RL circuit is represented by
Ldi/dt + Ri= V_o (1 + Be^-RT/L sint) u(t).
For an initial current of i(0) = V_o/R, the steady state value of the current is given by [2 marks]
(A) i(t) → V_o/R
(B) i(t) → 2V_o/R
(C) i(t) → V_o(1+B)/R
(D) i(t) → 2V_o(1+B)/R

asked in Electronics and Communication Engineering, 2009

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656.

In the circuit shown, what value of R_L maximizes the power delivered to R_L?

[2 marks]
(A) 2.4Ω
(B) 8/3Ω
(C) 4Ω
(D) 6Ω

asked in Electronics and Communication Engineering, 2009

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657.

The switch in the circuit shown was on position a for a long time, and is moved to position b at time t =0. The current i(t) for t >0 is given by

[2 marks]
(A) 0.2 e^-125t u(t) mA
(B) 20 e^-1250t u(t) mA
(C) 0.2 e^-1250t u(t) mA
(D) 20 e^-1000t u(t) mA

asked in Electronics and Communication Engineering, 2009

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658.

An AC source of RMS voltage 20 V with internal impedance Z_s = (1+2j)Ω, feeds a load of impedance Z_L = (7+4j)W in the figure below. The reactive power consumed by the load is

[2 marks]
(A) 8 VAR
(B) 16 VAR
(C) 28 VAR
(D) 32 VAR

asked in Electronics and Communication Engineering, 2009

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659.

The eigen values of the following matrix are

-1 3 5

-3 -1 6

0 0 3

[2 marks]
(A) 3, 3 + 5j, -6- j
(B) -6+5j, 3+j, 3-j
(C) 3+j, 3-j, 5+j
(D) 3, -1+3j, -1-3j

asked in Electronics and Communication Engineering, 2009

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660.

Match each differential equation in Group I to its family of solution curves from Group II.

Group I Group II

P. dy/dx = y/x
1. Circles

Q. dy/dx = -y/x
2. Straight lines

R. dy/dx = x/y
3. Hyperbolas

S. dy/dx = -x/y

[2 marks]
(A) P-2, Q-3, R-3, S-1
(B) P-1, Q-3, R-2, S-1
(C) P-2, Q-1, R-3, S-3
(D) P-3, Q-2, R-1, S-2

asked in Electronics and Communication Engineering, 2009

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