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In the circuit shown below, assume that the voltage drop across a forward biased diode is 0.7 V. The thermal voltage Vt = kT/q = 25 mV. The small signal input vi= Vp cos(ωt) where Vp= 100mV.
[1] The bias current IDC through the diodes is [2 marks]
(A) 1 mA
(B) 1.28 mA
(C) 1.5 mA
(D) 2 mA[2] The ac output voltage Vac is [2 marks]
(A) 0.25 cos(ωt) mV
(B) cos(ωt) mV
(C) 2cos(ωt) mV
(D) 22 cos(ωt) mV
asked in Electronics and Communication Engineering, 2011
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