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187.

Match items in Group 1 with items in Group 2, most suitably.

Group 1 Group 2

P. LED 1. Heavy doping

Q. Avalanche photodiode 2. Coherent radiation

R. Tunnel diode 3. Spontaneous emission

S. LASER 4. Current gain

[2 marks]
(a) P – 1, Q – 2, R – 4, S - 3
(b) P – 2, Q – 3, R – 1, S - 4
(c) P – 3, Q – 4, R – 1, S - 2
(d) P – 2, Q – 1, R – 4, S - 3

asked in Electronics and Communication Engineering, 2003

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188.

The electron concentration in a sample of uniformly doped n-type silicon at 300 K varies linearly from 10¹⁷/cm³ at x = 0 to 6 × 10¹⁶/cm³ at x = 2µm. Assume a situation that electrons are supplied to keep this concentration gradient constant with time. If electronic charge is 1.6×10^-19 coulomb and the diffusion constant D_n = 35 cm²/s, the current density in the silicon, if no electric field is present, is [2 marks]
(a) zero
(b) -112 A/cm²
(c) +1120 A/cm²
(d) -1112 A/cm²

asked in Electronics and Communication Engineering, 2003

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189.

An n-type silicon bar 0.1 cm long and µm² in cross-sectional area has a majority carrier concentration of 5 × 10²⁰/m³ and the carrier mobility is 0.13m²/V-s at 300K. if the charge of an electron is 1.6×10^-19 coulomb, then the resistance of the bar is [2 marks]
(a) 10⁶ ohm
(b) 10⁴ ohm
(c) 10^-1 ohm
(d) 10^-4 ohm

asked in Electronics and Communication Engineering, 2003

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190.

The impedance parameters Z₁₁ and Z₁₂ of the two-port network in figure are

[2 marks]
(a) Z₁₁ = 2.75Ω and Z₁₂ =0.25Ω
(b) Z₁₁ = 3Ω and Z₁₂ =0.5Ω
(c) Z₁₁ = 3Ω and Z₁₂ =0.25Ω
(d) Z₁₁ = 2.25Ω and Z₁₂ =0.5Ω

asked in Electronics and Communication Engineering, 2003

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191.

The driving point impedance Z(s) of a network has the pole-zero locations as shown in figure. If Z(0) =3, then Z(s) is

[2 marks]
(a) 3(s+3)/(s²+2s+3)
(b) 2(s+3)/(s²+2s+2)
(c) 3(s-3)/(s²-2s-2)
(d) 2(s-3)/(s²-2s-3)

asked in Electronics and Communication Engineering, 2003

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192.

An input voltage v(t) =10√2 cos (t + 10°) + 10√3 cos (2t + 10°)V is applied to a series combination of resistance R = 1Ω and an inductance L = 1H. The resulting steady state current i(t) in ampere is [2 marks]
(a) 10cos(t+55°) + 10 cos(2t+10°+tan^-12)
(b) 10cos(t+55°) + 10√3/2 cos(2t+55°)
(c) 10cos(t-35°) + 10 cos(2t+10°-tan^-12)
(d) 10cos(t-35°) + 10√3/2 cos(2t-35°)

asked in Electronics and Communication Engineering, 2003

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