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397.
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398.
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399.
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400.
Statement for Linked Answer Questions :
A 30-Volts battery with zero source resistance is connected to a coaxial line of characteristic impedance of 50 Ohms at t = 0 second terminated in an unknown resistive load. The line length is that it takes 400µs for an electromagnetic wave to travel from source end to load end and vice-versa. At t = 400μs, the voltage at the load end is found to be 40 Volts.[1] The load resistance is [2 marks]
(A) 25 Ohms
(B) 50 Ohms
(C) 75 Ohms
(D) 100 Ohms[2] The steady-state current through the load resistance is: [2 marks]
(A) 1.2 Amps
(B) 0.3 Amps
(C) 0.6 Amps
(D) 0.4 Ampsasked in Electronics and Communication Engineering, 2006
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401.
Statement for Linked Answer Questions :
Consider a unity-gain feedback control system whose open-loop transfer function is:
G(s) = (as+1)/s2
[1] The value of “a” so that the system has a phase margin equal to π/4 is approximately equal to [2 marks]
(A) 2.40
(B) 1.40
(C) 0.84
(D) 0.74[2] With the value of “a” set for a phase-margin of π/4, the value of unit-impulse response of the open-loop system at t = 1 second is equal to [2 marks]
(A) 3.40
(B) 2.40
(C) 1.84
(D) 1.74asked in Electronics and Communication Engineering, 2006
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402.
Statement for Linked Answer Questions ::
Consider the following Amplitude Modulated (AM) signal, where fm < B.
XAM(t) = 10 (1 + 0.5 sin2πfmt) cos2πfct[1] The average side band power for the AM signal given above is:
[2 marks]
(A) 25
(B) 12.5
(C) 6.25
(D) 3.125[2] The AM signal gets added to a noise with Power Spectral Density Sn(f) given in the figure below. The ratio of average sideband power to mean noise power would be: 
[2 marks]
(A) 25/8NoB
(B) 25/4NoB
(C) 25/2NoB
(D) 25/NoB
asked in Electronics and Communication Engineering, 2006
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