The average monthly income of P and Q is Rs. 5050. The average monthly income of Q and R is Rs. 6250 and the average monthly income of P and R is Rs. 5200. The monthly income of P is:
Let P, Q and R represent their respective monthly incomes. Then, we have: P + Q = (5050 x 2) = 10100 .... (i) Q + R = (6250 x 2) = 12500 .... (ii) P + R = (5200 x 2) = 10400 .... (iii) Adding (i), (ii) and (iii), we get: 2(P + Q + R) = 33000 or P + Q + R = 16500 .... (iv) Subtracting (ii) from (iv), we get P = 4000. P's monthly income = Rs. 4000.
Q. No. :
2
Question :
In a group of 6 boys and 4 girls, four children are to be selected. In how many different ways can they be selected such that at least one boy should be there?
We may have (1 boy and 3 girls) or (2 boys and 2 girls) or (3 boys and 1 girl) or (4 boys). Required number of ways = (6C1 x 4C3) + (6C2 x 4C2) + (6C3 x 4C1) + (6C4) = (6C1 x 4C1) + (6C2 x 4C2) + (6C3 x 4C1) + (6C2) = (24 + 90 + 80 + 15) = 209.
Q. No. :
3
Question :
In a fibonacci series, difference between squares of 6th and 7th terms was 517. What is the 8th term.
A :
32
B :
65
C :
83
D :
None
Answer: D
Q. No. :
4
Question :
A Candle Burns in 6 Hrs..Another Candle of the same height and width burns in 8 Hrs...After How Many Hours the height of the first candle will be half of the second Candle....
Two trains 140 m and 160 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time (in seconds) which they take to cross each other, is:
A person starts from the origin of the coordinate axis . He travels in
this pattern . 1 unit to right , (1/2) units up , (1/4) units right, (1/8)
units down , and continues the above pattern . At what point will he
ultimately come to stop?
Now displacement along the x axis - 1 + 1/4 + 1/16 + .....
this is , 1/(1-1/4) = 4/3
displacement along the y axis - (1/2-1/8) + (1/32-1/128) + .......
this is (3/8)(1-1/16) = 2/5
Q. No. :
8
Question :
There are five nos. a,b,c,d,e having value of 2,5,6,10,4, not necessarily in this order. We have following clues
1) c + a = e 2) e + a = d 3) d-b = b
Which of the following is true ?
A :
10-5 = b-d
B :
4 + 6 = a+e
C :
4-2 = b-d
D :
None
Answer: B
Q. No. :
9
Question :
476 ** 0 is divisible by both 3 and 11. The non-zero digits in the hundred's and ten's places are respectively:
Let the given number be 476 xy 0. Then (4 + 7 + 6 + x + y + 0) = (17 + x + y) must be divisible by 3. And, (0 + x + 7) - (y + 6 + 4) = (x - y -3) must be either 0 or 11. x - y - 3 = 0 => y = x - 3 (17 + x + y) = (17 + x + x - 3) = (2x + 14) x= 2 or x = 8. x = 8 and y = 5.
Q. No. :
10
Question :
Ramu is given Rs 382 in one-rupee coins. He has been asked to
allocate them into a number of bags such that any amount required between Re
1 and Rs 382 can be given by just handling out a certain number of bags
without opening any of them. What is the minimum number of bags possible?
whenever such a problem is given the key usually lies in powers of 2
or 3. So i tried with powers of 2 ( since we cannot open a bag )
the various bags he can have are, 1, 2, 4, 8, 16, 32, 64, 128, 1, 2, 4, 8,
16, 32, 64 ( since 382 = 255 + 127 )
that is 15 bags, so the answer is A
Q. No. :
11
Question :
In a shop, cost of 3 burgers, 7 milkshake and french fries is Rs. 120. In the same shop, cost of 4 burgers, 10 milkshake and french fries is Rs. 164.5. Find the cost of 1 Burger, 1 Milkshake and french fries in the shop.
Subtracting (i) from (ii), we get,
1B+3M=44.5 ...........(iii)
Multiply (i) by 4 and (ii) by 3 and subtract (i) from (ii), we get,
2M-1F=13.5-----(iv)
Subtract (iv) from (iii) , we get,
1B+1M+1C = 31.
Q. No. :
12
Question :
A student got marks in the ratio 6:7:8:9:10 in five subjects having equal maximum marks. In all, he scored 60% marks. In how many subjects, he got more than 50% ?
A boat takes 90 minutes less to travel 36 miles downstream than to travel the same distance upstream. If the speed of the boat in still water is 10 mph, the speed of the stream is:
Let the speed of the stream x mph. Then, Speed downstream = (10 + x) mph, Speed upstream = (10 - x) mph. 36 /(10 - x) - 36 /(10 + x) = 90/60 (72x )* 60 = 90 (100 - x2) x2 + 48x + 100 = 0 (x+ 50)(x - 2) = 0 x = 2 mph.
Q. No. :
14
Question :
Two trains are running in opposite directions with the same speed. If the length of each train is 120 metres and they cross each other in 12 seconds, then the speed of each train (in km/hr) is:
Let the speed of each train be x m/sec.
Then, relative speed of the two trains = 2x m/sec.
So, 2x = (120 + 120)/12
=> 2x = 20
=> x = 10.
Therefore Speed of each train = 10 m/sec = (10 x 18 /5)km/hr = 36 km/hr.
Q. No. :
15
Question :
A man buys a watch for Rs. 1950 in cash and sells it for Rs. 2200 at a credit of 1 year. If the rate of interest is 10% per annum, the man:
S.P. = P.W. of Rs. 220 due 1 year hence = Rs. [(2200 x 100)/(100 + (10 x 1))] = Rs. 2000. Gain = Rs. (2000 - 1950) = Rs. 50.
Q. No. :
16
Question :
How many kilogram of sugar costing Rs. 9 per kg must be mixed with 27 kg of sugar costing Rs. 7 per kg so that there may be a gain of 10% by selling the mixture at Rs. 9.24 per kg?
A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road?
Area of the park = (60 x 40) m2 = 2400 m2. Area of the lawn = 2109 m2. Area of the crossroads = (2400 - 2109) m2 = 291 m2. Let the width of the road be x metres. Then, 60x + 40x - x2 = 291 x^2 - 100x + 291 = 0 (x - 97)(x - 3) = 0 x = 3.
Let the ten's and unit digit be x and 8/x respectively. Then, 10x + 8/x + 18 = 10 x 8 /x + x 10x2 + 8 + 18x = 80 + x2 9x2 + 18x - 72 = 0 x2 + 2x - 8 = 0 (x + 4)(x - 2) = 0 x = 2.
Q. No. :
20
Question :
Two pipes A and B together can fill a cistern in 4 hours. Had they been opened separately, then B would have taken 6 hours more than A to fill the cistern. How much time will be taken by A to fill the cistern separately?
Let the cistern be filled by pipe A alone in x hours. Then, pipe B will fill it in (x + 6) hours. 1 /x + 1 /(x + 6) = 1/4 (x + 6 + x)/ x(x + 6) = 1/4 x2 - 2x - 24 = 0 (x -6)(x + 4) = 0 x = 6. [neglecting the negative value of x]
Q. No. :
21
Question :
A man complete a journey in 10 hours. He travels first half of the journey at the rate of 21 km/hr and second half at the rate of 24 km/hr. Find the total journey in km.
P, Q and S are moving on a circular stadium of circumference 2100 m. When P completes one round, Q is still 700 m behind. When S completes one round, Q is 300 m ahead of him. How far from the starting point three of them will meet for the first time ?
A :
16800
B :
256800
C :
2100
D :
None of these
Answer: A
Q. No. :
24
Question :
he sum of the present ages of a father and his son is 60 years. Six years ago, father's age was five times the age of the son. After 6 years, son's age will be:
Let the present ages of son and father be x and (60 -x) years respectively.
Then, (60 - x) - 6 = 5(x - 6)
54 - x = 5x - 30
6x = 84
x = 14.
Son's age after 6 years = (x+ 6) = 20 years..
Q. No. :
25
Question :
10 women can complete a work in 7 days and 10 children take 14 days to complete the work. How many days will 5 women and 10 children take to complete the work?
1 woman's 1 day's work =1/70
1 child's 1 day's work = 1/140
(5 women + 10 children)'s day's work =5/70 + 10/140 = 1/14 + 1/14 = 1/7
5 women and 10 children will complete the work in 7 days.
Q. No. :
26
Question :
How many 5 digit different nos. can be formed which is divisible by 4 from the digits 1,2,3,4,5,6 without repetition.
A :
144
B :
168
C :
192
D :
None
Answer: C
Q. No. :
27
Question :
The angle between the minute hand and the hour hand of a clock when the time is 8.30, is:
Angle traced by hour hand in 17/2 hrs = (360/12)*(17/2) = 255 º
Angle traced by min. hand in 30 min. = (360/60)*(30) = 180 º
Required angle = (255 - 180)º = 75º.
Q. No. :
28
Question :
Salaries of Ravi and Sumit are in the ratio 2 : 3. If the salary of each is increased by Rs. 4000, the new ratio becomes 40 : 57. What is Sumit's salary?
Let the original salaries of Ravi and Sumit be Rs. 2x and Rs. 3x respectively. Then, [(2x + 4000)/ (3x + 4000 ) = 40/57 57(2x + 4000) = 40(3x + 4000) 6x = 68,000 3x = 34,000 Sumit's present salary = (3x + 4000) = Rs.(34000 + 4000) = Rs. 38,000.
Q. No. :
29
Question :
A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if he is assisted by B and C on every third day?
(A + B + C)'s 1 day's work = 1 /20 + 1 /30 + 1 /60 = 6 /60 = 1 /10 .
Work done in 3 days = 1/10 + 1/10 =1 /5 .
Now, 1/5 work is done in 3 days.
Whole work will be done in (3 x 5) = 15 days.
Q. No. :
30
Question :
Train X starts from A towards B which is 180 Kms apart. At same time, train Y start from B towards A. Train X travels at speed of 70 kmph and Y travels at 50 kmph. While X does not stop anywhere on the way, the train Y stops at station C in between at 60km from B for 15 minutes. At what distance from A they would meet
Let the meet at a distance x km from A.
So x/70 = (180-x)/50 + 1/4
or, 100x/70 = 360-2x+25
or, 10x = 2520 - 14x + 175
or, 24x = 2695
or, x = 2695/24 = 112.3km
Six dice with upper faces erased are as shows.
The sum of the numbers of dots on the opposite face is 7.
Q. No. :
31
Question :
If even numbered dice have even number of dots on their top faces, then what would be the total number of dots on the top faces there dice?
If dice (I), (II) and (III) have even number of dots on their bottom faces and the dice (IV), (V) and (VI) have odd number of dots on their top faces, then what would be the difference in the total number of top faces between there two sets?
No. of dots on the top faces of dice (I), (II) and (III) are 5, 1 and 5 respectively.
Required total = 5 + 1 + 5 = 11
Q. No. :
35
Question :
If the even numbers of dice have odd number of dots on their top faces and odd numbered dice have even of dots on their bottom faces, then what would be the total number of dots on their top faces?
No. of dots on the top faces of the dice (II), (IV) and (VI) are 1, 1 and 1 respectively.
No. of dots on the top faces of the dice (I), (III) and (V) are 5, 5 and 3 respectively.
Required total = 5 + 5 + 3 + 1 + 1 + 1 = 16
Each of these questions are based on the information given below:
1. A ,B, C, D and E are five men sitting in a line facing to south - while M, N, O, P and Q are five ladies sitting in a second line parallel to the first line and are facing to North.
2. B who is just next to the left of D, is opposite to Q.
3. C and N are diagonally opposite to each other.
4. E is opposite to O who is just next right of M.
5. P who is just to the left of Q, is opposite to D.
6. M is at one end of the line.
If B shifts to the place of E, E shifts to the place of Q, and Q shifts to the place of B, then who will be the second to the left of the person opposite to O ?
B is opposite to O and second person left to B is Q.
Q. No. :
39
Question :
If O and P, A and E and B and Q interchange their positions, then who will be the second person to the right of the person who is opposite to the person second of the right of P ?
In the original arrangement who is sitting just opposite to N ?
A :
B
B :
A
C :
C
D :
D
Answer: B
Each of the following questions is based on the following information:
1. Six flats on a floor in two rows facing North and South are allotted to P, Q, R, S, T and U.
2. Q gets a North facing flat and is not next to S.
3. S and U get diagonally opposite flats.
4. R next to U, gets a south facing flat and T gets North facing flat.
Q. No. :
41
Question :
Which of the following combination get south facing flats?
4 people Arti, Banti, Chetan and Dolly have together got Rs100 with them. Arti and Banti together have got as much money as Chetan & Dolly put together. Arti has got more money than Banti. Chetan has half as much money as Dolly has. Arti has Rs5 more than Dolly.
Five offices in Mumbai are run by five couples
Husbands: Bala, Girish, Jai, Jayesh, Pratap
Wife: Beena, Chand, Maya, Preeti, Sangeeta
Surname: Bakshi, Joshi, Natwar, Parikh, Sahni
Office: Air India, Jet, Ashiana, Indian Court, American Court
No husband shares a first name initial with his wife
Only one husband who is not Pratap has an identical initial for his first name and surname, but none of the wives does
The Air India is run by Jai and his wife
Girish and Maya are one of the couples
Chand’s husband is Mr. Natwar
Mrs. Joshi is the owner of Jet and Preeti is the owner of American Court; neither of them is married to Jayesh
The office run by the Sahni has the word ‘Court’ as part of its name
The Ashiana is not run by Mr.Parikh whose wife is not Sangeeta
Five friends meet every morning at Sree Sagar restaurant for an idli-vada breakfast. Each consumes a different number of idlis and vadas. The number of idlis consumed are 1, 4, 5, 6, and 8, while the number of vadas consumed are 0, 1, 2,4, and 6. Below are some more facts about who eats what and how much.
i. The number of vadas eaten by Ignesh is three times the number of vadas consumed by the
person who eats four idlis.
ii. Three persons, including the one who eats four vadas, eat without chutney.
iii. Sandeep does not take any chutney.
iv. The one who eats one idli a day does not eat any vadas or chutney. Further, he is not Mukesh.
v. Daljit eats idli with chutney and also eats vada.
vi. Mukesh, who does not take chutney, eats half as many vadas as the person who eats twice as
many idlis as he does.
vii. Bimal eats two more idlis than Ignesh, but Ignesh eats two more vadas than Bimal.
Q. No. :
54
Question :
Which of the following statements is true?
A :
Mukesh eats 8 idlis and 4 vadas but no chutney.
B :
The person who eats 5 idlis and 1 vada does not take chutney.
C :
The person who eats equal number of vadas and idlis also takes chutney.
D :
The person who eats 4 idlis and 2 vadas also takes chutney.
Answer: C
Q. No. :
55
Question :
Which one of the following statements is true?
A :
Daljit eats 5 idlis
B :
Ignesh eats 8 idlis.
C :
Bimal eats 1 idli.
D :
Bimal eats 6 idlis.
Answer: A
Q. No. :
56
Question :
Which of the following statements is true?
A :
Sandeep eats 2 vadas.
B :
Mukesh eats 4 vadas.
C :
Daljeet eats 6 vadas.
D :
Bimal eats 3 vadas.
Answer: C
A, B, G and T are robots and P,Q, R, S ,T& U are machines. No robot can be assigned to more than 1 machine at the same time.
* A and B are required to run machine T
* Band G are required to run machine R
* G and T are required to run Machine P
* Machine Q can be run by only A
* Machine S and U can be run by any of the robots independently
Q. No. :
57
Question :
If machine Q is running which other machines cannot run simultaneously?
